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Integral with a Radical in the Denominator

Calculus 1000
Evaluate the integral: $$ \int \frac{1}{x^2\sqrt{x^2-9}}\,\mathrm{d}x$$
A$\frac{\sqrt{x^2-9}}{9x}+C$ B$\frac{\sqrt{x^2-9}}{3x}+C$ C$\frac{x}{9\sqrt{x^2-9}}+C$ D$\frac19\ln\left Ex+\sqrt{x^2-9}\right F+C$